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l J EEEW m 1.43 The two wooden members shown, which support a 20kN load, are joined by
plywood splices fully glued on the surfaces in contact. The ultimate shearing stress in
the glue is 2 8 MPa and the clearance between the members is 8 mm. Determine the
:10 kN 120 mm factor of safety, knowing that the length of each splice is L = 200 mm. PROBLEM 1.43 SOLUTION There are 4 SEPArdL‘l‘t evens (SF aloe. Each
3.999. area musl +ran3mﬁ+ 10 RN o'F sheet» foetal.
P :: tombs N Lena“: 0’? spptce L: 249 + C when. 49': apena'H‘t u'P'jpue anal C
Cpewfanc'e. P 1' éCL— C) = {1(OJDO “0.003) : 00‘i€ in.
Area. or 39.1: A: 2w = (0.0945(0J203 = “.52 Xlo'sm" much 49an Pa = ’tqu': (2.3310‘)(u.$2 we"): 32.256 :4th 3
rant.» or 539,47 ES.= _;sp9_ = W = 3.23 4 1.43 The two wooden members shown, which support a 20kN load, are joined by plywood splices ﬁJlly glued on the surfaces in contact. The ultimate shearing stress in
the glue is 2.8 MP3 and the clearance between the members is 8 mm. 20 RN 120 mm 1.44 For the joint and loading of Prob 1.43, determine the required length L of each
splice if a factor of safety of 3 .5 is to be achieved, PROBLEM 1.44 SOLUTION There are 4 Sepqwm‘l'e €1ch 6F 3.902... Each
«nice area musi ‘h‘ansmi‘l IO MU o? sheav
Peat]. P = leIOE' N
QequireJ UPHImvle In“! R; = (ESJCP) = (3.5Vl01lol): 353/01 H
Requires? JenaHr I a'PI emoln'ﬂpue area.  . 1: Pu “ﬁll—L ' 04 l? ’0‘:
Po ’L'uA  ’fuﬁw ’9 0W ‘(msxro‘XOMOJ I ‘ )f h LenaHa o‘P Spire: L= 22+: = (2t(toq.7xlo")+o.oos
= 216.3xlodm 2:6 mm “‘ ...
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