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32_Mechanics Homework Mechanics of Materials Solution

32_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: l '3‘, l—'—| l J EEEW m 1.43 The two wooden members shown, which support a 20-kN load, are joined by plywood splices fully glued on the surfaces in contact. The ultimate shearing stress in the glue is 2 8 MPa and the clearance between the members is 8 mm. Determine the :10 kN 120 mm factor of safety, knowing that the length of each splice is L = 200 mm. PROBLEM 1.43 SOLUTION There are 4 SEPArdL‘l‘t evens (SF aloe. Each 3.999. area mus-l +ran3mﬁ+ 10 RN o'F sheet» foetal. P :: tombs N Lena“: 0’? spptce L: 249 + C when. 49': apena'H‘t u'P'jpue anal C Cpewfanc'e. P 1' éCL— C) = {1(OJDO “0.003) :- 0-0‘i€ in. Area. or 39.1: A: 2w = (0.0945(0J203 = “.52 Xlo'sm" much 49an Pa = ’tqu': (2.3310‘)(u.\$2 we"): 32.256 :4th 3 rant.» or 539,47 ES.= _;sp9_ = W = 3.23 4 1.43 The two wooden members shown, which support a 20-kN load, are joined by plywood splices ﬁJlly glued on the surfaces in contact. The ultimate shearing stress in the glue is 2.8 MP3 and the clearance between the members is 8 mm. 20 RN 120 mm 1.44 For the joint and loading of Prob 1.43, determine the required length L of each splice if a factor of safety of 3 .5 is to be achieved, PROBLEM 1.44 SOLUTION There are 4 Sepqwm‘l'e €1ch 6F 3.902... Each «nice area mus-i ‘h‘ansmi‘l IO MU o? sheav- Peat]. P = leIOE' N QequireJ UPHImvl-e In“! R; = (ESJCP) = (3.5Vl01lol): 353/01 H Requires? Jena-Hr I a'PI emoln'ﬂpue area. - .- 1: Pu “ﬁll—L ' 04 l? ’0‘: Po- ’L'uA - ’fuﬁw ’9 0W ‘(msxro‘XO-MOJ I ‘ )f h Lena-Ha o‘P Spire: L= 22+: = (2t(toq.|7xlo")+o.oos = 216.3xlodm 2:6 mm “‘ ...
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