35_Mechanics Homework Mechanics of Materials Solution

# 35_Mechanics Homework Mechanics of Materials Solution - l...

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Unformatted text preview: l__ ‘ l l L l 1.4 7 A load I’ is supported as shown by a steel pin which has been inserted in a short . wooden member hanging From the ceiling. The ultimate strength of the wood used is 60 MPa in tension and 75 We in shear, while the ultimate strength ol‘the steel is 150 We in shear. 1.48 For the support of Prob. 1.47, knowing that b = 40 mm, c = 55 mm and d = [2 mm, determine the allowable load P ifan overall factor of safety of 3.2 is desired. SOLUTION Based on ale-35,9 Shem» in Pin Pu = ZATU': Q'Edlfu = IRIXO-OIZTMOWO‘) = 3333 we? N Bowed on +ension In wood Pu 7 AS“ = wlb-dlc‘u = (0.090)(0.090 — 0.012)(60x 10‘) =.- 57.2 no3 N Based on cloak}: shear in -Hue wood = ZA’I; = Quit-.21, = (2)(o.o-io)(o.osstswm‘) = 33.0 was N Us: snuffed Pu .- 33.0x10“ N Aﬁjovmlaie 13': "FEE;— : W3 .- l0.3l~l0’ N l0.3l RN ...
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