38_Mechanics Homework Mechanics of Materials Solution

38_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 1.51 1.51 Each of the steel links AB and CD is connected to a support and to member BCE by % — in.- diameter steel pins acting in single shear. Knowing that the ultimate shearing 1 in. , stress is 24 ksi for the steel used in the pins and that the ultimate normal stress is 60 ksi I ‘ for the steel used in the links, determine the allowable load P if an overall factor of mm, ". safety of 3 .2 is desired. (Note that the links are not reinforced around the pin holes.) SOLUTION Use rECE as “Fwee body 3 2 M3 = O BEs-i’O’P =0 P = -%‘F¢n mac: sag—129:0 P=§FIMI Bat-Ha .P‘mks have the same area anal same pin charted-er 3 hence, 52in? dF'HIe Same Irma-interim}3 flex, will have +he same ui‘i-a‘umi’c Jami. BaseaP on Pin in Sl'njfle sheaf A = its!" = £05)" = 0.1%35 in“ F0 = 70A .- (291(0- mass) =' 4.7m? kaias Based’ on +€M$fon in flihh’ A = (b—aIH: = (r- we) = 0-i25'in‘ E) = 63A = (60)(o.125)= 7.52: Rips Uj‘i'ihqqi'e goat) ‘For pink is smalles'l': F0 :- H.7l2‘l kilns. Miami/Lila flml 4% Pink Pegs-flail: mm; kips . o Afijomee foetal For S+F00+UP€ P = iéF 1" 0.53? ”(’35 F " 53‘? IA ...
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