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40_Mechanics Homework Mechanics of Materials Solution

40_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 1.53 1.53 Each of the two vertical links CF connecting the two horizontal members AD and EG has a 10 X 40- mm uniform rectangular cross section and is made of a steel with an ultimate strength in tension of 400 MPa, while each of the pins at C and F has a 20- mm diameter and is made of a steel with an ultimate strength in shear of 150 MPa. Determine the overall factor of safety for the links CF and the pins connecting them to the horizontal members. SOLUTION Use member EFG as fieelody. = o 0.40 1L;F ~(o.6=5')(mvto~") «3 0 24m Fe.- 3 3‘! x to“ N Baseel on least“! in [Rinks CF A = (5— al) I: = (0.040 -- 0.02)(o.0ro) = 200 no“ am“ COME-tic) F0 =2EUA= 62(400uo‘fl2oowd‘) r “30.0 x105 N Basset 0h clout-fig sheawfn Pi‘ns A = Eel1 = ‘E(o.020]z = snug x10" m" E, = 221A = (ZYIsox/ca‘Xsté no“) —- 34.248 «Ios N Adam)? F}, is smajjew Value) 3.9. F.) =' 94.248 “103 N s Far/low ol‘ Safely ES. 2': -% -.- W = 2.42 ’8 {“7” came-Mu 4!] : 'DDALIL; S Tfi F—T‘ ...
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