{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

41_Mechanics Homework Mechanics of Materials Solution

41_Mechanics Homework Mechanics of Materials Solution -...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: i": I :j 1.53 Each of the two vertical links CF connecting the two horizontal members AD and EG has 3 to K 40— mm uniform rectangular cross section and is made of a steel with an ultimate strength in tension of400 MPa, .while each of the pins at C and F has a 20- mm diameter and is made of a steel with an ultimate strength in shear of 150 MPa. Determine the overall factor of safety for the links CF and the pins connecting them to the horizontal members. 1.54 Solve Prob. 1.53, assuming that the pins at C and F have been replaced by pins with a 30- mm diameter. SOLUTION Use member EFG as Free. body. Bases! om +eh3t'ovi in [Pinks CF' . u. A = (hr-Jill = (0.040- 0.0So)(0.0to]=‘ IOO Noam (one Auk) 25M = czttuoovIO‘l(ww10") = 80.0H03 N 80-st on 400L792. shear in Pins A " %°"' = \$9.030? ‘-' 706.85 we"; in" F” = 223A = (2.)(t50‘ﬂ0‘ 300636210“) = 2:2.oexlo’ N Act-cal F], is snailer leue, Le. F“ 80.0 was N 3 Factor 9‘? sa-Pe‘i'y ES. 3 E” = Egg—«#33 : 2.05 i CF i ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online