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107_Mechanics Homework Mechanics of Materials Solution

# 107_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 2.60 A brass link (E = 15 x 106 psi 44, = 10.4 x 10"/°F) and a steel rod (E = 29 x PROBLEM 2.60 . b ' . t 10‘5 1:51, a; = 6.5 X 10"? °F) have the dimens1ons shoWn at a temperature of 65°F. The steel rod is cooled until it ﬁts freely into the link. The temperature of the whole assembly is then raised to 100°F. Determine (a) the ﬁnal normal stress in the steel rod, (b) the ﬁnal length of the steel rod. FA L5 in. t1 7 SOLUTION _L ‘T Wi-l D 1.5in. AT aamf~+d wi‘Hl olfWgnnc-e Be‘hleevt ‘anq.’ 0-005 in. -| L—10 ilk—4 l.25-in.\gameter m Steel L A Free ‘H‘lev‘mmp expansion at? 64.0% qu‘l' Brass PM]: ('51.); = 015931”th ammo"- K353Clul = 3.54xlo‘3 in \$+ee9 real (51-); ‘= OQQT XL) '-' (6.5xto“ )(MXlo) : 2.1"): no" in M He Final +empw~o~aluw2 ‘Hle ‘Fne .pal/taﬁ 9'? '1": steel? IP04 0.00S‘+ 2.275xto'3 - 3.64w0'5 = 3435210" in «Donner ‘Hlom “He. bus: pink As” «you! law} appeli'k 430W.“ ‘P +9 eponaul'e ‘Hne bro.“ .Pl‘nlt anal cowl-Mao‘l' 'Hse 5+"! real. and im‘ Hm? :1 the nsfolns smmn AT: loo — Gs 3§°F . - _El_-. .. 4927......“ BFASS Jlﬁk (Sp)b " AE " (2)0.5'X23CISXIO‘) = M.” no" P Sheba) (3,); = 7% = Poo) ) 350.25) (zewo‘ = 280.le x lo“?D (\$9., Hal 2 3.635Vto“3 (3‘72J0xlo'q)? = 3.43.9!!0‘3 P= 9.27on/o3 )1, ‘3 (130 Final) S'H‘GSS in \$410.9 W04 6; =--£- eaw q, . = —7.\$\$'x(ospsl‘ : -7..\$'\$' list -I on ma Juan. .l? shop NJ Lt- : 10.000 + 0.006“ + (31-); (Sp )5 = moon- 2.275ulo‘3 - (280. 6?? * (0")(q-27’35'“ ’0’) = ID. 0046') in. [:Il—W O f" l i i O L: l u ‘ WW 1 "1 \\ i4 l ...
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