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124_Mechanics Homework Mechanics of Materials Solution

# 124_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: (W \J _. _ L_.___J C} ﬂ, f L_._‘-J ‘ i PROBLEM 2 8 4 *2.“ Detennina the change in volume of the 2-in. gage lmgth segment AB in Prob. ' 2.68 (a) by computing the dilatation of the matm‘al, (b) by subtracting the original volume of portion AB ﬁ'om its ﬁnal volume. Frau-a P908 LEM 2.68 ‘Hm'ck "255 = 1% in E -: 2c? ,qo‘ r.“- ﬁnal}: v -= o. 30 600 ll) SOLUTION (61.) A =(%)(7lr‘j=' 0.03125 ulna \Iojuw‘e: 5U; = AL; -.: (0-03I25')(2.003 1. 0.0625 has 600 A 0. 03115 3 Eﬁ=EL(~G;'-.y6;d-2JQ\= \$2231.12 -.- 652.07xlo" E ,9} u f—o I! = 19.1 no? pa; 6} = 6; = o E 2qmo‘ z = - 22.5, = — (o.ao)(cc2.o7x10") = —l‘r8.62>¢lo" e. = 5, +2}. + E; :- 249.3s no" A‘D’ = 959. =(a;oc15)(264.23vlc>“) r 16. and" m3 -- (L) From He Sopu'i'ion. +¢= ’PROBLEM 2.62 s, = 1. 32mm“ in) SJ : — emswo“ in \$2: —I2.‘H¥lo“ g... The dimensions wken umJer a. 600 lb -|-emn‘l-e J9me! mm: j¢n3+h L: 1.0+ 5,, 2 2+ /.32~r yzo'i = 2.001324 m. wiaH'L w= W9+\$7= J5; 619.950“ = 0-4‘i'iaoov in. 'Hu'okness t= t,,+ 31—— gig—mmwo" =- 0.0624215? ;... Volume ‘1)”: Lwt = 0.0525195” in?‘ Mi -= ‘U- “U; = -0.0615’16\$3°l - 00613' = IG.\$"+Y[0" if“ ...
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