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133_Mechanics Homework Mechanics of Materials Solution

# 133_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 2.93 5w: (‘93 N ho’e 8 K6...“ - 2.93 Two holes have been drilled through a long steel bar that is subjected to a centric axial load as shown. ForP = 6.5 kips, determine the maximum value of the stress (a) at A, (b) at B. SOLUTION A+ hope A J- (a.l Y‘:'§-1= 0J0 From F13 2.699. -. (2.7o)(5.2) - 14.04 ksf r = i055: 0.75) Am» = dt = (1.5%“le j: _ 0.1: = 0.5 0.75' in: From Fla 2.6‘ta d . 1-5 Snag ‘ K6}... (mergers/3 =- 18.2 ks: 2.94 Knowing that aall = 16 ksi, determine the maximum allowable value of the PROBLEM 2'94 centric axial load P. SOLUTION 6.2 =(1.25‘)(46) F —- 2.70 7.4] k-ps “31(15):- 0.75;") A1: = 0.5m.) = 0.75 :3) 0.75' L5— "' 0-5. FM“- Fl-j QC? 0. _ A...+€:.., _ (0.7mm) .. — n m K 2,10 " Smaﬁper Vat/Pu: 4394* 1: con‘l‘mjs J: 3—1.5:- 1.5;". K= 2.“: 5. 7' Mr”. P: 5.7] k5ps ...
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