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167_Mechanics Homework Mechanics of Materials Solution

# 167_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 2.135 The steel tensile specimen ABCD (E = 29 x 106 psi and cry = 50 ksi) is loaded in tension until the maximum tensile strain is e = 0.0025. (:1) Neglecting the effect of the ﬁllets on the change in length of the specimen, determine the resulting overall length AD of the specimen alter the load is removed. (b) Following the removal of the load in part (b), a compressive load is applied until the maximmn compressive strain is e = 0.0020. Determine the resulting overall length AD after the load is removed. PROBLEM 2.135 5‘0 x103 E 2‘? x105 5...“ : 0.0025 > Er Yl'ejdinj aceurs in lowfi‘oln BC :- O_OO I724 E .2" I ll 68¢: 6Y 3 50*10‘313‘3; Permanem‘i 45+an in BC. E,“ = Ehw- EY = 0.0025 - 0.001729 = 0.000776 In reverse} .9090“an) 43" For’n‘l' E on siress-s'l-min pier} - O. 0020 8 0.5 jive-n. Darrin? Penman/cup o‘F ‘Huz Y‘eUeV‘Seal 190w!) Hue ohmae {m sin/him {S 6} /E = 0.00f72‘}. The. Permancmi 5+rm‘n In BC is £3; = — 0.0020 + 0.00:72L1: o. ooonc ‘53: = LE“: (1+)(—o-oooz76) = -o.oonoq in. 4 No‘i'e ‘Hm'i' Par-“hon: AB anal CD are Juno’s ep¢5+ch 'Hqus ‘Hneu'v' agormdions Aldrin“) vPDLJinj and quoadc'na oil) ho'i Coh'i'u/‘L'btl'i‘e 4!: any per‘wmn en‘i’ ale-rou/‘mavi’fom. ...
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