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185_Mechanics Homework Mechanics of Materials Solution

# 185_Mechanics Homework Mechanics of Materials Solution - i...

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Unformatted text preview: i H O IO 3.17 The solid rod AB has a diameter d“ = 60 mm The pipe CD has an outer PROBLEM 3‘17 diameter of 90 mm and a wall thickness of 6 mm. Knowing that both the rod and the pipe are made of a steel for which the allowable shearing stress is 75 MPa, determine the largest torque T which may be applied at A. SOLUTION 1".” = 15:10“ Pa To” = Jig” Chi-A a 0.9mmJ J=§Ec" To.» = 3:3 Zw =-' g (o.oso)3(75up°) = 3.18! no“ Mum Pipe 03: c2 = 2M; 20.045 m q: 51" t :- emf-0.99.6 = 0.036: m J = %(sz_ Cf) = E(0.04\$“- 0.03?) = 2-8073 xirj‘ W.“ Tau ._: g .8073er“ )(75 x106} : 9.573),“)! N-m 0.045- Aﬁﬁowa’ble 'l‘cwtue is He smallpox Value CEJSMO3 N-ml 3.13 kan-d PROBLEM 3 18 3.18 The solid rod AB has a diameter d, = 60 mm and is made ofa steel for which ' the allowable shearing stress is 85 MPa. The pipe CD has an outer diameter of 90 mm and a wall thickness of 6 m; it is made of an aluminum for which the allowable shearing stress is 54 MPa. Determine the largest torque T which may be applied at A. SOLUTION Cr:‘9l:cl= 0.030 m :§(0.03033(35xm‘)= 3.605210% Nan ‘RPQ CD: fti‘xlO‘ ’Pa. C1: 3'? C, = C2— t = 0.0s5‘- 0.006 a 3 '= ELCJ- cf) = J§(o.oss“— 0.039“) = 2.8073 no" w.“ Tau?! - J :l—————2‘8073 “04)(sq‘yl06) = 3,367VI03 Hum " 6.. 0.045 Aﬂo‘wtahpe iowque. is small?” value TI”: 3.39%6103 N-m 3.37 RN-M ...
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