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189_Mechanics Homework Mechanics of Materials Solution

# 189_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: F—T O 3.25 Under normal operating conditions a motor exerts a torque of magnitude T; at PROBLEM 3-25 F. The shafts are made of a steel for which the allowable shearing stress is 12 ksi and have diameters of dew; = 0.900 in. and a'mﬂ = 0.800 in. Knowing that rD = 6.5 in. and SOLUTION r6 = 4.5 in., determine the largest torque TF which may be exerted at F. rm 1' ‘2 1‘!" 5519+ F-‘G: c =éd = 0.400 ‘m ‘ , J’E _, 'IT 5 Eu“ “6:?! - “2‘ C t” T .—_ 1T(c>.m:o)3(lit\= Moe Lop m. ShacP'l: DE: c=éal= 0.950 in '- 7’77 kt‘P’lVI 1;)”: gig— (1.7177) : Lia-'7 kip-in AMOWaln/l’e quue 0'? Ti: is +an smdﬁef‘ T5414 :3 LIS? kiP‘I‘n ‘ 3.26 The two solid shafts are connected by gears as shown and are made of a steel for which the allowable shearing stress is 60 MPa. Knowing that a 600 N-m—torque TC is applied at C, determine the required diameter of (a) shall BC, (1)) shaft EF. SOLUTION Shelli” 8:7 Tc z 600 Nd" ) 21km: QOX'O‘ PO. -;T_c.__2_: 7') d' hitce - 3.. 2:: : (2)5600} C‘ ' 'IT’C “(Gomoﬁ c - 13.53 xio’5m= \$.53me Aéc=2c=32 [ mm : 6.3662: 10“ m“ a = gig—(coo): 375' N-m ¢3= % ’ £331.?)- = 3-9737“; "‘3 c : £5,85W0'5 m = 5.83%.") 015;: 2c =3:,7m ...
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