{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

230_Mechanics Homework Mechanics of Materials Solution

# 230_Mechanics Homework Mechanics of Materials Solution -...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 3.86 A 1.6-m-long tubular steel shalt (G = 77 GPa) of42-mm outer diameter d, and 30-m inner diameter d2 is to transmit 120 kW between a turbine and a generator. Knowing that the allowable shearing stress is 65 MPa and that the angle of twist must not exceed 3“, determine the minimum frequency at which the shaft may rotate. PROBLEM 3.86 SOLUTION C, = ”7'3" = 0.02! m, CL : 31:0); = 0.015.“ ﬁg“): 1,509,021"— o.oa<"‘)= 2251?? no" m“ Bessel om s-lwss Rum-Jr ”z: :- 65' MPa._= GSXIO‘ Pa. ‘1'— J?! __ (225.4:7210‘93CGSX10‘W ' C. ‘ 0.02.: Basaé an aunt)“. 6P +w€s+ piwi‘l’ CP ‘-‘ 3° 6‘1-3CY104M c? = I], ‘._ T = G-JQ = (77x10‘7C225'ﬂ7wo‘9)(€3.36H04) 6-.3' L (.6 = mean. um 56?.40 10-»: Small)” lbw-qua. governs T 569.90 U-M P= 010 w = (20x (05 W P=2n¥T ¥=~5§\$= mono" _______.___ 2 H 27T(56‘I.‘fo) 33.5"! 2‘ r ZOIZ P?“ ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online