Unformatted text preview: PROBLEM 3 99 3.98 The solid circular shaﬁ show is made of a steel which is assumed to be
' elastoplastic with 1'}, = 21 ksi. Determine the magnitude Tof the applied torque when
the plastic mmis (a) 0.6 in. deep, (b) 1 in. deep. 3.99 For the shaﬂ and loading of Prob. 3.98, determine the angle of twist in a 4ﬂ
length of shaft. SOLUTION c: 1.25;”, 21.: 2: k5: = zrxlo‘ pan") eatzuo‘rsl L: i'\F‘I' 1433“ 1;]; _ (49%?! Ho“; '3
 _—_ =  M
C 9 (1.251012 ”(0‘) 7? 00210 .5
pi, = ctyu mgrox. = 0.65 45“ O 5  c. " LZS
= F252 : 7:52:30” 2 l32.‘l§’/0.$V‘°J = 193.,
f I pp ct, =I.25'—1.o a 0.25‘ q!
C? 33% = 72020;"“l0 =' 360 :46st PROBLEM 3 100 3.100 A torque '1‘ is applied to the 20mmdiameter steel rodAB. Assuming the steel
' to be elastoplastie with G = 77 GPa and 7,, = 145 MPa, determine (a) the torque T when the angle of twist at A is 25 ° , (b) the corresponding diameter of the elastic core
of the shaﬂ. SOLUTION
Lrl.5m1 G=77¥lo “a. _LTr
CPY'GC _ (:.5)(H$x:o‘)
09" ‘ (77x107)(o.0lo) Ty 1’ $3.61? = latest; 2 ¥(0.OIO)SCV+S VIO‘) ? 227.77 NM 282.47 x lo" mt  s .47. 0'3
g) = 25° = 43433xro‘ mt > cp, gt: M ._. 0.69737 (‘13 T = :3: Ts? ( '  ﬁ 335%!) = %(227.77)[1 zi(amsﬂﬂ = 223 Man «a (5) gr 2 0.5q737 ,or = 0.9973? c = (0.64737)(o.om) 6.4737 vzo'sm .~ 6.14737 m». av: 2p, = 12.75 mm ...
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