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246_Mechanics Homework Mechanics of Materials Solution

246_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 3.1 l 1 3.111 A 50-mm—diameter cylinder is made of a brass for which the stress-strain diagram is as shown. Knowing that the angle of twist is 5° in a 725-mm length, determine by approximate means the magnitude Tof the torque applied to the shaﬁ. SOLUTION a? =' 5° = 87.2é6yio'3 ran-3 c :1” = 0.025 m) L = 6.725% - g? H (0.0%)(27-236wo" z 0 003:»: TM ‘ L ‘ """"o-725 ' =I .. ”i z 'r...‘ ‘5 l i T = 211' Soc/02¢ eff) = 271.61.502.21, Jz= 27123.1— wiene He in‘i‘CjV‘aaP I is jinn LY 1-:nger1 Ewai’uwi? I Using a. me'le oi? nameh'eaf in+ejmuifum I‘F SimpSM‘s Wk is 0524) 4+8 ihiearai‘w‘m pormvﬁa. is where w is at we,“ L‘i'z‘uj 43mdi’w. Using A2 1' 0.15"’ we je’i‘ +3”. VHJJCJ given in Hue “help e beﬂovd. szzz’ a = 233.7910“ Pa I": 0-15") ”3.75“” = 2%.65‘xto“ Pa, 3 T: 9:561” = 2ﬁ(o,oas]’(23.s\$x 10‘) =- 2.32xzo‘* U- M = 2.32 kN-M ...
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