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278_Mechanics Homework Mechanics of Materials Solution

278_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 3.156 A sheet metal strip of width 6 in. and 0.12 in. thickness is to be formed into a PROBLEM 3-156 tube of rectangular cross section. Knowing that ran = 4 ksi, determine the largest torque that may be applied to the tube when (a) w = 1.5 in., (b) w = 1.2 in, (c) w m r___w_.:|: lin. SOLUTION per u' Me} Bro amt . Am. 5°.)an a, “sews-m OL= wd * wt; .. m firing-:3. T=2tO/t’= 2tw(§—wlfi Data; 3 = 0.12:“, F” 6 an, ”r = 4 km (a) w-= LS T: (2 )(oumcLsxtmm '= 2.:6 kip-{v1 (H W: L1 T = L2Xo.12)(t.z)(l-3)CH) = 2.07 kept.“ Lo} w-.~ Lo T: (2 )(mcz 11.0)(7-0 3C4 3 = Lam kip-iv. The qujes‘i' Jfiowqiie +orque CONESPDneLS +0 9. squaresedn'on. 3.157 Two solid brass rods AB and CD are brazed to a brass sleeve EF. Determine PROBLEM 3.157 the ratio dzld, for which the same maximum shearing stress occurs in the rods and in the sleeve. SOLUTION Le‘l’ C. = ‘7L.a' GIMO‘ C1 = Jz'dg TC. hf sum AB . v 3.— figs, 2. 59 E F Tc; = _TC_a.'._ :3 22¢: J1 Tl" Cat-C." or X'-' 11.71446. Sail/c [by Successive afpruximuf'fons s+ar+fnj whH‘ Xe: 1.0 I} 76.=- "4?: was , 961: was = 1-7.14 mar-72.2“; =}.1Zo cap-‘72:” = mm 1.24.: (convey-jay!) x= L221 - 1.221 r/!\ U L__JL"_l [—ie—JE—JL g4 Liv—l [:1 Tn" ! ...
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