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344_Mechanics Homework Mechanics of Materials Solution

344_Mechanics Homework Mechanics of Materials Solution - in...

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Unformatted text preview: in 4j0M1'nUw n=!.0 Yl“ Ei’“§i§- = 3.0 in sixeeriJ 51mm II = n, 1}(V§'—n") = (3.0)71’206310“) = 130.85xI03 mm" APWWM.‘ I; Hz 1300". n-“)..—(r.o )1; (Ht/é“) = $0.38'XI03 W.“ I: 12,4112 = 18l.73 wag mm” = :21..73x.zo"' m" C9“) Afuw‘numz: c '-= H Mm = 0.0!? m :ILMQ, (LOKSOONOJH) _ 3 c = HP «1 6' 1 m—-—-——-—‘m.73 X10“ .. 5'2. X10 fit 52.3 a. (b) She-.9.- C = lémm = 0.016 n nMg _ (3.036500)(o.olé) .— c __ I _ W -1152on Pa 132.: MPQ - PROBLEM 4.66 4.6.6 Solve Prob. 4.65, assuming that the 6-mm—thick inner pipe is made of alummum and that the 3-mm—thick outer pipe is made of steel. 10 mm SOLUTION Use domino.“ as fine V‘e'PewencI; m+ewroJ VI = L0 in afiuufinvm _§a=.&9_= , g _ 5., 70 30 make]. 51ml): I. = n.’l§(¥‘."-r‘.e") '-“ (3’0)¥09“— I6“) = :52,“sz m" Momma“: 12 = nz%(ro“-r;”)=(l.o)-$(Ie“~Io") = 43.e2.x/o’ m.“ ‘- I. + I; = ”6-27%!03 m." = Jeanna" m” (a) AaPuu-num . C: 16 MM = 0.0:; I». 6" hIMC ’ "316 33x13 = wexm‘f‘a = Lia-8 ”P4 " (5) Size)? = C. = 19 MM = 0.0!"! w. _ gaolgsoo Mame) ‘ 196.2%!0" G :- 1' = Hileo‘fl. = 193.2 MP4. '- ...
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