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356_Mechanics Homework Mechanics of Materials Solution

356_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: (bi N M the top and bottom of the bar are 20 mm thick. 20 mm SOLUTION I I 20 mm ‘_t_ (03 Im+ = J; Lia‘s-.- “-(4030503- 720N03 mm“ 20 mm 20mm = 706.87xlo" w: " MM: 0.030M M I: so.§2tiowo‘)(7oe £7on 3 Y C O. 030 : 5.C5333i03 N-M = 5.65 kU‘m 5'! A! E- = 62,13, 2 (ZRDxp‘iCQOQoxaozo) = l‘t‘Zon‘ N 'Ohna.+’OMm = 20 Imam "—‘ 0.020 m Rf Jim; fiCNDV'O‘XO-Ozoxo'wo} = 24,,03 N y: .— 3400“) = 6.66%“. = 0.006667 M 2 (1?. y: + Pig/:3 2[(1°|2*103)CO.010) 4 (24x103)(o. 006667)] = 8.00rIOsN-m = 8-00 loo-w. lake-11‘ ‘1‘ \2 HELP: [11,2°3(20)3 ‘1" 13-33 Nos MM? 10mm“'| L—J L—lOmm I ‘: 7207103— 8.33%?” = 706.67Vios mm” 4. 83 and 4.84 A bar of the cross section shown' is made of a steel that' 13 assumed to PROBLEM 4.34 be elastoplastic with E= 200 GPa and a,— — 240 MP3. For bending about the z axis, y determine the bending moment at which (a) yield first own-s, (b) the plastic zones at ‘ ...
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