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360_Mechanics Homework Mechanics of Materials Solution

# 360_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 4.87 thmugh 4.90 For the bar indicatad, PROBLEM 4.88 (b) the shape ﬁwtor of the cross section. 4.88 Bar of Prob. 4.84 determine (a) the fully plastic moment M}, y WT SOLUTION 20mm I —+ Frau PROBLEM 9.84 E: 200 519“ (ml 6:, =2'1lo Mag“ 2 20mm ﬂ!!!- 91 = (StrA. 10mm—‘l L—'|20mm L-lOmm =QHOXIO‘)CO.O‘/b)(0.010) :: 192 7103 N j, '- lOMM‘F‘O‘HM :2OMM = 0.020m P2. = 635‘: = (zqowto‘Xo. 010303.010) = #834103 N J2 -‘~ 3:500) '-' Sum ‘-' 0.005m M, r 2' (9.], + .353 = 2[(I‘t2 uto'mﬂzoi + Gama-(0.00531 = 8.16““?! MM 1' 8.]é [NU-m 4‘ (19) IM =ﬁL|n3 = Til-(403(60): -' 720wzo’rm’ Iw’roui- '-' ﬁbks= ﬁﬁaoﬂao)’ r I3.33x103- m..." I - Ln): - I‘m = 72mm“ — 9.33%“ = 7oe.c7 m“ m." = 706.67xzo" w," c=ﬁk '-' 39mm = 0.030Im Mr .-. 52.1: .,. Moultg‘gggé-‘WW-q) :- 5.6533: N-M M ‘ 3.16 '3 4 :- -—-—-—- 3 . 3 ‘ k M1 5.5533 l L” ...
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