363_Mechanics Homework Mechanics of Materials Solution

# 363_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 4 9] 4.91 and 4.92 Determine the plastic moment Mp of a steel beam of the cross section ' shown, assuming the steel to be elastoplastic with a yield strength of 240 MPa. SOLUTION "Fa-lap area A = (Selma—(30%“) = 3600 M...” 'I... I 3A = 1800 .m J‘ 1800 ‘L: '2 —l p. A, : (SoXac) = 1300 m‘, 3, = :8 pm A5}, = 32.9 >40“ mm: A1 =. (50)(l‘l)'~=' 700 m: 32 = 7 an.“ ALS’; '-‘ LL? x [03 mm: A3 7" (2°)(30) = 600 Mar) 33 ' Zﬁ MM A; 33 ' l-IJ'} X {03 mm: Al. “ (50)(l0) " 6.00 ”M: g“ :- LH MM Auk-Yb" e 24.5!1'03 MM 2 AfiwAaSu syn/M3? = mean = szo' £ 3 M, = GIVE/4&9; = (zqono‘3(7a.nxzo“) H.008H03 M-m = I‘LOJ kN-w -I ...
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