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393_Mechanics Homework Mechanics of Materials Solution

393_Mechanics Homework Mechanics of Materials Solution - l...

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Unformatted text preview: l l 4.131 Knowing that the allowable stress is 150 We in section 0-0 of the hanger PROBLEM 4,131 shown, determine (a) the largest vertical force P that can be applied at point A, (b) the . l , l 7 .. . ., 7 , .t .. . ., corresponding location of the neutral axis of section a-a. SOLUTION Luca-lg, Cdfl‘h‘ofci 2A 2900 2.“ 50mm The cen'i'rofaf pics 50 um +6 'He "3H. thK’ 'Hno JQH‘ (3de o"; 'Hle sedl‘t'ovu Bendix-n3 Coupje M = P6 3 ? [+0 +50 = ‘70 MM = 0.090 M 'f 7‘5- (2o)(eo)3+ (memo? = 840x103’ mm II = I2- = 341' (“XZOY’ +(lzoo)(2o)" r 520 :10“ rm“ 1: t '1 I,+ Iz 1' l.360><l06wn :- l.3€oxlo"‘m“ J A= 240mm“ m“ (a) Baseol on +ensl‘J’e sires: a+ Pef'l eAJe: J = —50 mm = -o.05‘0 u. KP ..___. ____..———«(°‘°70)('°'°5°3 = 3 7255x103 H" 2400x166 L360 >410"- ' =% = l+4:>..’5’x10”M = 40.5 M1 (in) Lac-diam of neg-IMP 9.; f5: (3‘: o _ E ._ Pay i. - .1. 6 ‘ A I ‘ O i A .~ _I___ ‘_ Lawsuit)“ : 6.30X10‘3h r 6.30 w... d Ae, (24001l0“)(0.0?o) T138 H6U+raj curI'S pie-5 6.30 MM +0 'H-Ie hfaL‘} o'r ‘Hte ten-hora! or 56.30 mm {mm +Le JeH ealje ...
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