{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

393_Mechanics Homework Mechanics of Materials Solution

# 393_Mechanics Homework Mechanics of Materials Solution - l...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: l l 4.131 Knowing that the allowable stress is 150 We in section 0-0 of the hanger PROBLEM 4,131 shown, determine (a) the largest vertical force P that can be applied at point A, (b) the . l , l 7 .. . ., 7 , .t .. . ., corresponding location of the neutral axis of section a-a. SOLUTION Luca-lg, Cdﬂ‘h‘ofci 2A 2900 2.“ 50mm The cen'i'rofaf pics 50 um +6 'He "3H. thK’ 'Hno JQH‘ (3de o"; 'Hle sedl‘t'ovu Bendix-n3 Coupje M = P6 3 ? [+0 +50 = ‘70 MM = 0.090 M 'f 7‘5- (2o)(eo)3+ (memo? = 840x103’ mm II = I2- = 341' (“XZOY’ +(lzoo)(2o)" r 520 :10“ rm“ 1: t '1 I,+ Iz 1' l.360><l06wn :- l.3€oxlo"‘m“ J A= 240mm“ m“ (a) Baseol on +ensl‘J’e sires: a+ Pef'l eAJe: J = —50 mm = -o.05‘0 u. KP ..___. ____..———«(°‘°70)('°'°5°3 = 3 7255x103 H" 2400x166 L360 >410"- ' =% = l+4:>..’5’x10”M = 40.5 M1 (in) Lac-diam of neg-IMP 9.; f5: (3‘: o _ E ._ Pay i. - .1. 6 ‘ A I ‘ O i A .~ _I___ ‘_ Lawsuit)“ : 6.30X10‘3h r 6.30 w... d Ae, (24001l0“)(0.0?o) T138 H6U+raj curI'S pie-5 6.30 MM +0 'H-Ie hfaL‘} o'r ‘Hte ten-hora! or 56.30 mm {mm +Le JeH ealje ...
View Full Document

{[ snackBarMessage ]}