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395_Mechanics Homework Mechanics of Materials Solution

# 395_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 4.133 Knowing that the clamp shown has been tightened until P= 75 lb,dctem1ine PROBLEM 4.133 in section 0-0 (a) the stress at point A, (b) the stress at point ,(c) the location of the neutral axis. SOLUTION Luca/+9. semi-void '2 0.4739 11. 1-1.: “Ame? ﬁre. 0.473? m. aim Fowl ‘D. Bemolthﬂ Coup]? M: Pe e, = —(2+ o.8~o.47397= - 2.326: in II -_- IJi(lr_;,q)(o.;5)-"+ (0.064)(a.72-0.4?59)" r 4.013 x163 M It: ﬁ(o.lél(m.64)3+(0.1029Ko.4573‘i-o.52)2= 532} “0'3 W I = I. + I: =’ “haBﬂXiO—s in“ (<1) Sircss 6-} Poi-«4' A: J: 0.3- 0.473? ‘-' 0.326! in 6 = E. _ L431 , _‘E___ Pry _(75)(—2.s26:)(o.326l) A A 1 A wen—«1 16139 “0-5 7-” ’EJB H05 f5“ = 6.19 161' "i (b) S‘l’ress aJl‘ Fowl .D .- X = -,O.Ll'1%9 in, = 0.1%! .‘u _ .P. _ M e 7; 75 4.325: +0.37%) 6:1’ A j; A Bf!” 0.166? ‘1954 Mo” = —7.37 No In: '-' -.7.87 ksu' «a (c) Loco-J‘Ian a; ﬂed'l'V‘Aap am's 6= O .. .E _ _. _ Pe _ 2.! = .L 6‘ A g¥ 'E ii " o .I A 1; mast-jun" = “'0.0257 in “'3 CI = T 7' (oJGé‘iX—ZBICH The neulwﬁ axis 1):” amaze-0.0257 = 0.448 in. aLwe Pain‘l‘ D. ...
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