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458_Mechanics Homework Mechanics of Materials Solution

458_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 198 4.198 The split ring shown has an inner radius r1 = 16 mm and a circular cross PROBLEM 4' section of diameter d = 32 mm. For the loading shown, determine the stress at (a) point A, (b) point B. 2.5 RN SOLUTION II,— (32§“= 2051.25 m‘ = 80%.25Ho" w.‘ P = 2.5103 N M = PF =(2.5x;os)(3zuo“) = so U-m to.) Poiml A: n = mesm— IS = 13.354? W _ My ‘_ 2.5::10‘ (90303.8:‘frlo'33 Aer. - 809.25,:{0‘ (80?.25'Kto"}(2.\Yééulc")(lé*[0") = -Hs‘3 Ho‘ flag. 2 -‘+3.3 MFR. d $1.854? - H8 =° -l8.HSG w... __ 25xlo‘ __ (sub-lamacno"? somsxmd (semisartd‘ )(11H36wlo‘3X48x :0-5 ) 19.93::10‘Pa. = 14.43 mm - ...
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