484_Mechanics Homework Mechanics of Materials Solution

484_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 4.C2 - CONTINUED W (MM/m were WP c : 6/2 or: 5205.: :zv'Cf/ONJ "Ev” 0} 5; 5% fi‘fiéx’c'tp" 5v) W R7: % 0} t” 5)’ 3.9202”; Mong-rr PHD/y; Q x: cm VflTUNE . p -.— g” A: Q} @MHM : kf‘?’ w zxppé‘swg Fo/C; cam ma RY) Fo/a'n = I "7'0 '7. Fan 3),: a: 72> (6%?) 47 —z‘.—/,’2 DzeceiME/v?! ' 9 A: cozy/P074: M=2 2”" an.” More. 97:.- / 79¢ 40% to = O—t—F" 732%, (pf/1,7 f Fro/2 5Y7 {CPZLQJ 7'0 16/? («17‘ I-éF/Z fiEc/ést-wn“ 9 f f w CCJ/wpuzar M: 7.399.604 flog “r123; 7074‘?“sz 37' / 7W5»; Pic/”z y ””907" Nil/”£65760!— VALUES film) ram ppédmwt {PM/97M a 0 WU?" For a beam of Prob 4.218 Depth (1 = 140.00 mm Width of flange bf = 120.00 mm Thickness of flange tf = 10.00 mm Thickness of web tw = 10.00 m I = 0.000011600 m to the 4th Yield strength of Steel sigmaY = 300 MPa Yield Moment MY = 49.71 kip.in. YY(mm) M(kN.m) rho (m) For yielding still in the flange. 70.000 49.71 46.67 65.000 52.59 43.33 60.000 54.00 40.00 For yielding in the web 60.000 54.00 40.00 55.000 54.58 36.67 50.000 55.10 33.33 45.000 55.58 30.00 40.000 56.00 26.67 35.000 56.38 23.33 30.000 56.70 20.00 25.000 56.97 16.67 [u m. . 1 - : . ...
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