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516_Mechanics Homework Mechanics of Materials Solution

# 516_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 71m 7—1 g r“: [:1 5.33 Determine (a) the distance a for which the maximum absolute value of the PROBLEM 5.33 bending moment in the beam is as small as possible, (b) the com: 11 . xim normal mes due to bending. 8‘” dmg ”‘3 “m ( 20 IcN 40 IN (Hint: Draw the bending—amen: diagram and then equate the absolute values of the largest positive and negative bending moments obtained) I SOLUTION g W360X64 Readi'ion 4+ 8 'QZMC : 0 20a. -(2.4)(uo)+(1+.o)8 = o 8* 24 - 5' :1. Bending manner} 0:} 'D ‘ GM 3 93MB : O 3 53 -~ + 1. L‘ 8 MD:- La. 8 r 33.4 - 8a, - Beneiinﬂ momewT ad' C 2° M DZM¢=O ' D 20a+M=O ‘ j [*0- v M==-20a. { E30538 "" Me 1' Mg ( 20 Q :- 33.“ " 80. Q. '-' L37!” m 4 Mc 7 47120: mm MD-a 21mm kN-M ; For W 360: 6‘! “Meal size! sec‘l'i'on 5 = IoSox [03 m3 = loaowlo“ m‘ i . ‘ 3 .\ Norm-u? dress 6‘= lgl ‘4' W ‘-' 26.61:!0‘91 ‘-' 26.6 “Pa. 4 l ...
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