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520_Mechanics Homework Mechanics of Materials Solution

520_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 5.37 SOLUTION PM: bad} EFGH Nah. Hi} M5 = 0 0'0‘ +0 hx'nae. 92 M5 2 O 0.: H-(o.2i.(«+u:-(o.4:)(soo) - O H: JTF = 213.3: N Vg-4o-3oo+au3.33=o w 124-61 N E +oF F +9 G- GhH 12$.G‘7 U-M 86.67 MM V =- V 2 V = -2t3.33 N-m emu»: hone-d a‘l‘ F' 9214.. = 0 Mr -(o.2JC12¢.c7) = 0 Mr :- 25.33 N'IM Banding momen‘l‘ «4 G '9: M. '3 O - M; « (0.2)(2:3.33) = 0 MG I: ”2.67 N'") 213.33 +9? Me '= o 300 zoo mm c a A 1) +32%. = 0 Bench»: mound d‘ B OSMS : — mas-ms) v m. = 0 M3 = 5:.“ U-m Bending mommf d C +93. Mc '- o -(o. u Kan-:2) +(o. 2 )(3oo) , + M; = o M.._ :' 42.” Mm Bendin: meme-1'! a} D 43 2.”. 2. O . - M. -(o.23(2:3.331= 0 Mo = -' 25-33 N-m Free bad! ABCDE -O.6 A +(0.‘! )(aoo) +(0.2)(300) 40.002441) = o A2 257.79 N ‘-(O.2N3001 — (0.4)(3001 -(o.2)cm.a7) ‘+ o.cn = o D = 468.8? N "1‘.le 3 51.56 N-m s = 1-5? = %(zo)(3o)‘ '-'-' 33'0' bums: 3%IO“M3 . Norma! shes: 6 1. til-56 = leo" I'M“! Ilo‘ P1 = '7. 1? NPR. 5.37 and 5.38 Draw thc shear and bending-moment diagrams for the beam and loading shown and determine the maximum nomlal stress due to bending " ...
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