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558_Mechanics Homework Mechanics of Materials Solution

# 558_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: L__.1..A L ‘ 5. 74 BeamAB supports two concentrated loads P and Q‘ It has been experimentally PROBLEM 5'74 determined that the normal stress due to bending on the bottom edge of the beam is +15 MPa at C and +22 MPa at E. (0) Draw the shear and bending-moment diagrams ( ‘ for the beam. (b) Determine the maximum normal stress due to bending which occurs in the beam. g 160mm For reo‘l'ahgupar cross sedh‘wx Se‘bh“ ‘ S =(le(24 )(COY :- HHMOé mm‘ .- l‘l.‘l xlo" m3 1 Bendinj momBn‘}: at} C and E M= 36‘ i Mc=(l‘f.‘tk10"Xl\$’<lO‘) = 216 N-m ME=(H.qu:o“)(mb‘) - 816.3 N-m 1 Using Podium AC. as a 'PNQ body 4‘; Me. D§M¢= O -‘O;3A + Mc 1 D A’ 7720 N -' A Aﬁﬂv +12'FJ =0 A-V; =0 Vc, = 720‘ N Using Par-+50“ CBS «.5 a. ‘FN; boat), ”6 P E 9 in: = O D 0.3P-0.SVc—M¢+M‘=o Vt. o.1—~LO.3 V; P g 364 N ( MEI-3:0, Vc-P—VE=O vE=-mq~ J For‘Hon EFB as a. 'Free Baal-7 Q JOE-Mg: O 0.2Q-0.” V. - ME = O v: 1.1,“ B 0.: I196 N “28:0, V.-Q+B=vo, 82“!qu Areas 1)an Shea» cling-MM Battalion) Momen‘l‘s: Mg= 0 me D (6.51729) -_ see 91-». MD : o + 860 -- 360 Mn 0+:- F (o-sx-fmv -72 N-m MF : ago-7st = 233 Mm F to B (O-ltht‘Wi‘xez'S's'NM MB : 293-288 = o Maximum “'4‘? 360 N~m ' d M Normal S‘l’nss G" “131'? ﬁ= 25"!0‘ Pa =- ZSMP-L --I E ...
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