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562_Mechanics Homework Mechanics of Materials Solution

562_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: L__A§ j L—J { ___A} Lib} L45 ”:3 igl 2 L_4 I lag; ] i4] 3 - s“;“1 "4‘ ‘ 2.]‘5110 ifimdinorthebt-amandloadingsho dcsi ' .79 . . wn, gn the. cross scatter: of the beam, PROBLEM 5 knowmg that the grade of nmber used has an allowable normal stress of 12 Mpa. 3W“ SOLUTION +5 Me, = o -2.«+ A +(o.c\(3.cj(33 .— o A 22.7" km “OMB: o —u._s)(a.6)(s) +2.43 = o 3:23.: w v;-— 2.1 «(2.9mm —- - +5 m: w:-4.5‘+8.l r 3.4 m \4_ = 3.4- (mus) = 0 Low“: ?o3v\+ '13 when V e o 3% : 21:: 7.2 J: 6J4? ,1.- o.qm 2-9-:1: 1.5m Areas UnAer shear can}: A in 1) 3w» = @Konkm) = 3.215 w.” 0 +. B SU-‘y : (iXI.s)(.-q.s) = —3.375' kU-M B h: c SW: = (é)(1.2)(3.c) = 2.1:. L’M-m Bending meme-n+3: MA = 0 Mn = o + L215“ c 1.215 w-m MB: Law-3.37:: = -2.Ié {AI-m Mc.’ -2.I‘¥2.l‘ 9 0 Maximum ‘M‘ =' 2J6 kU‘M ’ 2.!6I'l03 ”-3“ 6;" : l2 MPaz. = lzxto‘ Pa 6m :2: lot. mono" m3 = 180 x lo“ MM: For «dam?!»- «when 3-.- {bh‘ :- {His-o? :- Iaoxlo‘ Lb=flLQL I) '-‘ 98mm' 150'- ...
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