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565_Mechanics Homework Mechanics of Materials Solution

565_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 5.81 and 5.82 Knowing that the allowable normal stress for the steel used is 160 PROBLEM 5.82 Wa,.selcct the most aconomical metric wide-flange beam to support the loading shown. 50 kam SOLUTION DEM» =0 — 3.18 + (2,4)(3.2)(5o) = o B = I20 kw +3'ZM3: O 3.2T.) -(o.s\(3.2)(50\ = o D = 1+0 kw Skew/‘1 VA=0 v3- = o ~(o.s)(5o) . «40 W Vg+ = —'-!-0+ 120 -- 80 W V: = 90 - (2H)($o)- um w VD: -'-}0+0 = -‘IOle 1 | f—\ nguJ .. L_fi+J A WVJ [:— w .1 LOCm+e Pctu‘f E where. V= O- a. _ 2.4-3 __ E3 - Milo [202 192 er 1.6 m 2-¥-e=o.3m. . Areas? A +0 ’8’ SVJY = GYD-SX‘”) :- .. 1g, kw-" ‘ 8 +:. E Swy *(iYJAMeo) = 94 mm E +0 C S VJx =(=k)(0.8\(-~to) = - h; kU-m c; +u D Svah.t = -(O,B)(-‘fo) , — 32 kU-m Bending momen‘l's: MA = 0 ME, = O-lé '= -16kU-M ME = —lé+6‘l r 43 mm. Ma: 43— 16 ~— sakwm MD : 32. " 32, ‘3 O M&k;flnu|~\ "’1' 3 “8 “1-!“ “- Q8¥I03 N-M 6.19 =' 160 MP4. '—' IGOxIO‘ 1’41 3 .. 5 It)8 MM.) MW”? LfflHes‘} wide £91m? beam W250 X 23.4 9 28.4 [ta/M W Woman ...
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