{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

580_Mechanics Homework Mechanics of Materials Solution

# 580_Mechanics Homework Mechanics of Materials Solution -...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: fﬁﬁJ [:3 LHLJ L ”mi 12,4 L‘___J '4_1 i 5.97 Determine the largest permissible uniformly distributed load w for the beam PROBLEM 5.97 shown, knowing that the allowable normal stress is +12 ksi in tension and — 19.5 ksi in compression. B=C HEW Sheavl VA: 0 V3-3 0- SW 2 '8“! V3+= —8w+IS~W-‘ 10w V.-.-= law-20w =—ti Va '-* -’.lo.w + 13 w = 8w V9= fur—3w = 0 Areas? A A8 'liWJHSwl =42 w B +0 E (#XIoXIO w) : 5'0 w Benahns MomP-n'fs? Mh=o Me, = O - 32W " '32!) Ma -‘ ~31“: +50 w :-' I8w Can't-MRI anal momen‘l‘ a‘P Inerfl'a. Gm“ -C""‘ A (m‘) dint L 8989 0.7‘HO 1.5:): 2.625 Run”) . 0.9492 0.01“ 1-6875 LIRS. 11348" 0.75 I 0.944: o_7|a_‘q_ﬁ «40.15 '- 13P; 321425 I0 = 2.5106 :w‘ 89mm: 2/9.].375‘ 1:6, :- -1.qs:c3 i.’ Bendinﬂ Momen‘l' Pim’h M '-' - GI/y TGN‘M'OIG n1 8 Adel C " (123( ‘2. aﬂoﬁ) : "‘ 22.‘37 ‘0'?- I'm Cod-ill. ad Bud c - (4153(- msusl = —17.=m MP4“. 4 Tans-fan ~+ E -(I2Y- LHS‘IS) = I12”. kip in “<3 Compression d E _ (415 )(a.3qoe )=- ”(.6 (a... r... A’pouJ-le )vol w B F C - 32 w =' - 27. 46‘! w: 0.87? k'P /.'n E 13 W ’ I7. 212 W =' O. 75‘ kw: ”a SMJJCS" W? O. 87" MP [in 1-" IOJJQ kl? [H- "‘ l . l J ...
View Full Document

{[ snackBarMessage ]}