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580_Mechanics Homework Mechanics of Materials Solution

580_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: ffifiJ [:3 LHLJ L ”mi 12,4 L‘___J '4_1 i 5.97 Determine the largest permissible uniformly distributed load w for the beam PROBLEM 5.97 shown, knowing that the allowable normal stress is +12 ksi in tension and — 19.5 ksi in compression. B=C HEW Sheavl VA: 0 V3-3 0- SW 2 '8“! V3+= —8w+IS~W-‘ 10w V.-.-= law-20w =—ti Va '-* -’.lo.w + 13 w = 8w V9= fur—3w = 0 Areas? A A8 'liWJHSwl =42 w B +0 E (#XIoXIO w) : 5'0 w Benahns MomP-n'fs? Mh=o Me, = O - 32W " '32!) Ma -‘ ~31“: +50 w :-' I8w Can't-MRI anal momen‘l‘ a‘P Inerfl'a. Gm“ -C""‘ A (m‘) dint L 8989 0.7‘HO 1.5:): 2.625 Run”) . 0.9492 0.01“ 1-6875 LIRS. 11348" 0.75 I 0.944: o_7|a_‘q_fi «40.15 '- 13P; 321425 I0 = 2.5106 :w‘ 89mm: 2/9.].375‘ 1:6, :- -1.qs:c3 i.’ Bendinfl Momen‘l' Pim’h M '-' - GI/y TGN‘M'OIG n1 8 Adel C " (123( ‘2. aflofi) : "‘ 22.‘37 ‘0'?- I'm Cod-ill. ad Bud c - (4153(- msusl = —17.=m MP4“. 4 Tans-fan ~+ E -(I2Y- LHS‘IS) = I12”. kip in “<3 Compression d E _ (415 )(a.3qoe )=- ”(.6 (a... r... A’pouJ-le )vol w B F C - 32 w =' - 27. 46‘! w: 0.87? k'P /.'n E 13 W ’ I7. 212 W =' O. 75‘ kw: ”a SMJJCS" W? O. 87" MP [in 1-" IOJJQ kl? [H- "‘ l . l J ...
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