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581_Mechanics Homework Mechanics of Materials Solution

# 581_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 5.97 Determine the largest permissible Imifonnly distributed load w for the beam PROBLEM 593 shown, knowing that the allowable normal stress is +i2 ksi in tension and - 19,5 ksi in compression. 5. 98 Solve Prob. 5.97, assuming that the cross section of the beam is reversed, with the ﬂange of the beam resting on the supports at B and C. SOLUTION Rem/haw; E+C~3éw=0 B=C=12w Shear? VA=O V5: 0 —8w e -8w V3=-3w+l8w=loiu ‘19 r iOvu- 20w -* -JOw V3 —iow+l?w= 8w V°=~SWv8w= 0 Areas?‘ A +o B (HUN-12w) wszw '3 +0 5 (“Gt-)(toiu') = 50w Bewoir'nj momen‘l’s: MA = 0 MB = O‘3Qw 2-32“! Ma r-3QW+SOw -= iﬁw Cevi'i'mi‘A and manned a‘Pincr'Hm. _ Gas) A (if!) Ad‘tin‘) I Cw“ 0.7”"! Q07‘1\ Bend in: momen+ (pin-'+S Tension ad' and C ~(I2)(I.H3H33 Comp. d Band C -(Hq;\$a(- 2.3mm Tension a5“ E —(|23(-:2..3<l05) Compression ad‘E -(‘-l?‘.5‘)(-l.1l3'-l3) - mm. mm. ._. -'%.6 ku'f-in '234387 k:r‘ in 27.4w tap-3.. -— :1 II 1| I] Alﬁoudh 1"“ W‘ 3‘ C '32“: = - 17.2”» wa 0.531 "-‘r ’i. E '3 U "’ 27. qéq W LSSI} kip/fa Smﬂes-i w -.- 0.531. kilo/in -= us In}, In 4- ...
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