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623_Mechanics Homework Mechanics of Materials Solution

# 623_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 5.147 A cantilevered machine element of cast aluminum and in the shape of a solid of revolution of variable diameter d is being designed to support a horizontal concentrated load P as shown (a) Knowing that the machine element' is to be of constant strength, express d in tenns of y, L, and do. (6) Determine the maximum allowable value of P if L= 300mm,do=60rmn, and arm=72 Mpa. PROBLEM 5.147 SOLUTION A 1? §ZMJ=O -M~Pj=o Cs H so I . 1T6” __ Pi _ 31 P '3 E'“'*”‘3 “2753' 62w 0' ' am?) a, / . . VS I3 A+y=’- d=éo=‘313\$,7 22,41?) "‘ - - Wﬁ' _‘___°624 T 0050} (72xto‘)_ s SJuma Po.» 1’ ’P —3———1L = _'L._____(32)(0_ 300) 5.09540 N = 5.0‘? kill ‘- 5.l4_8 A cantilevered machine element of cast aluminum and in the shape of a solid of PROBLEM 5-143 revolution of variable diameter d is being designed to support a horizontal distributed load w as shown. (a) Knowing that the machine element is to be of constant strength, express d in terms of y, L, and do. (b) Determine the smallest allowable value of do if L = 300 mm, w = 20 kN/m, and 0,“ =72 MPa. SOLUTION For a. soﬁt‘ol circa)“ cross seeit'on Q: ‘31 _ _ g _ ire} _ 776’: = 111:" 5 ’ c ' T ’ 32 at“ _ w " _ IGWIZ ”3 Equa‘i'mj %_ " 31%.” d _( 116.1 ) L“ I}; y ”5 M x= L a! , a '—~§§Lu) 0': aMt) “ . - OJW}4 = 50.9104». USMj H“ Ad“ cL—fi 'lT (72*!0“ : 50.3 mm d ...
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