686_Mechanics Homework Mechanics of Materials Solution

# 686_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: [—5 ' l -__m] 1 my] .L___ .J l I L444 L_J___ A :1 6.25 Two W200 x 46.1 rolled steel sections are to be welded at A and B in either of the two ways ehown to form a composite beam. Knowing that for each weld the allowable horizontal shearing force is 500 kN per meter of weld, determine the Emmi!!! allowable shear in the composite beam for each of the two arrangements own. PROBLEM 6.25 SOLUTION For rolled sfeeﬂ see-Hon W ROOHJQJ l. A =- sseo m a: 203 n... b‘: = 203 um I. = #515 “ohm“ I: = 15.3uto“ Mml' I = ZlL + My] = 2[ 45'.\$~rlo‘ +(ssso)(32°—")‘] = zunvio‘ rm" = ZH.7)‘/D‘6 m‘ Q = A; = te'seottia‘ial = 5‘54.8Ho’ m»? = 6“M’.8xto" m3 3‘ = 500 kN/M ‘For one. weld. For 2 weld}: (3.44? lOOO kU/M VQ - I .1! __ t2!!.7wo“\(loaono\$)ﬁ x 1 7‘“ T V“. 73:. ' S‘MLBIIO“ ' 356 to N = 356 kN I : 2[IJ+ Naif]: 2[is.3xio‘ + sseotz—‘g-Y] = 15'qu sqo‘ m." = 151-34 Ho“ m. G. = A 31‘ ’ (subway): Seams wilt): mm‘ c 5?4.3v10" m3 : IQ?» __ (15l-:‘lq:08"3C‘:-:D‘OIIO') , 254,103“ = 254 w 4 ...
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