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721_Mechanics Homework Mechanics of Materials Solution

# 721_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: mt—i L : 1”] at 711—) L_ .1 i 1 +1 'i-ﬁ ' I—l“ 6.65 and 6.66 An extruded beam has the cross section shown. Detennjm (a) the location of the shear cutter 0. (b) the distn'btnion of the shearing stresses caused by a 50-kN vertical shearing force applied at 0. PROBLEM 6.65 SOLUTION A.” guani’n'hes in MM: m1 c+¢n Ina. = -0°XM‘+ momma): o._n1333x:o‘ M I” F! (ammo) + ,T'a-l.(7o)(c)-" = l.OS.|26nlo‘m-u" I“ = \$003000)” =- 0. 83333: :o‘ m.“ I = Z]: ’ 3.7C’ZSIHO‘ mm" o (x-to) w»: ,9) .. I .. 6 J Q= Aj= 5(3- to)(j+ to) -5 (y - :96) =5(50 ~Ioo)- mrxo’ m" EMA S _.L_1__Vz 5‘2"”) 2.5 to 3 . 3 ‘ (F-wowiﬂ 3:- “W FM :L5_L____3€-€‘7*’°3) : 0.048726- 336st ID ‘ Q3 + (GxXSo) =_ £2,405 + 300 x f;- %% Q» = Keno” + (3°0X70) " 33 ribs mm To 1W 4 F= S Z’JA S W1” z 31S02r1053ooﬂh - -[l‘2rl03)x+3m 39f) = (”“03 70')+(3uo 701/2 ’ 7- 3.7a: x :06 3 5. V = 0.41360 392 m - 3% Va = 2F. ("rah moor (2Ko.o4272eVXvow+ (O-Lti‘sébVMloo) :' \$3.7 lV 6? 48.7 mm "‘ A+ Foia+ H Q, =- Q” + (toxsoxas) = 33xlo‘1» {2.9403 P which...“ Conﬁnuect ...
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