756_Mechanics Homework Mechanics of Materials Solution

756_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 6.C1 6.61 A timber beam is to be designed to support a distributed load and up to two concentrated loads as shown. One of the dimensions of its uniform x rectangular cross section has been specified and the other is to be determined x 4 so that the maximum normal stress and the maximum shearing stress in the 2 . . . P beam Will not exceed given allowable values a," and ran. Measuring x from to end A and using SI units, write a computer program to calculate for successive cross sections, from x = 0 to x = L and using given increments Ax, the shear, llll'“lll *itl'“ the bending moment, and the smallest value of the unknown dimension that -:_--, ",‘j ' :"‘-."--'-. '7 _‘-' " ' ' " '1), satisfies in that section (1) the allowable normal stress requirement, (2) the al- I I. 3 J lowable shearing stress requirement. Use this program to design the beams of a b SOLUTION uniform cross section of the following problems, assuming 0'51] = 12 MPa and 1-,“ = 825 kPa, and using the increments indicated: (a) Prob. 5.75 (Ax = 0.1 m), (b) Prob. 5.76 (Ax = 0.2 m). 566. solubon 0+ P5. CZ fer the determination of RA) Em W1) arIrIML'c) We recall That J J V001” 73;; STPA + Rs S‘TPB - ESTP1~ P2 grpz -4U {1—9: E,) STP3 + MOI-1:05 W4 W1) = Rn (70695773151 + R3 (x—a ~ L) 57?}; - )3- (22—105fo 492 (z-XL)STPZ-%w (1'19”:ij +§ wa—xufg-rp 1+ til—heft 5779f] 5TPfi 5W4 . _ . {’uncfions deffined in Pé'jc—é—PZ,5TP5,CI/M 577% are: 5T6)“: (1) ' M45171“ TH I'iF'Uhlcnewn dimmeivn is h: 5;“, =IMi/(7aj/ , From :szfh: WC hare hGZ/lzi/éS/t If (mm/mum airfieflbt‘on LS E 5:14.14 z!M"|/g;” ‘ r’rom 5:2“? We have to: [—7 65/172 (2) 7‘0 sarlsry Tfii Anew/ante sesame SFR‘EfiS '73 Wé'vse .(6/ ' . refit/T_ 3N , E? D);Pa36373.. imam _ ZZEL ,___:QUIREM£NT? t" cw)“ NWT If units/mun alimensmn is in: H’ Uhkmou/n dimension )5 3: (CONTINUED) ...
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