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773_Mechanics Homework Mechanics of Materials Solution

# 773_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 7'13 7.13 through 7.16 For the given state of stress, determine the normal and shearing stresses after the element shown has been rotated through (a) 25° clockwise, (17) 10° counterclockwise. SOLUTION 5, :-'+0MP« <35: GOMPa 73:20 HPa. gig-93 = 10 MP“ -\$o MPa 6;“: 547?": + gal—5‘3 @329 + If,” sin29 ‘ _§y;_6'1 Sin 29 4 7’.” ms 26' * Sic—(S; 2 0:526 -- “.Y sin29 —- 25° 20 = —50° [0 - .50 695650.) + 20 so. (—50") =- -3?.5 MP. + 50 sin (-50°) + 20 005 (-50“) = -25_‘-} MPa ’0 +50 ca: 050') " (’0 Sin (-50") = 57.3 MPG. (a e = to” 29 = 20° to -50 095(1qu + 20 Simaoo) = - 30.! MPa +50 sin (10') + 20 ”5(20'3 '-‘ 35.“! MPG. 63. 1-. IO +50 cosmo") — 20 5:420"): 50.1 MPq ...
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