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776_Mechanics Homework Mechanics of Materials Solution

776_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: ‘\ \_ L) J PROBLEM 7.16 16 ksi counterclockwise. SOLUTION 6“ = 0 SJ M6 55 = 3 ks.‘ — u ‘6 k‘u‘ 7.13 through 7.16 For the given state of stress, determine the normal and shearing stresses afier the element shown has been rotated through (a) 25° clockwise, (6) 10° '0 last M- -31“; 2 - ,:m + MCOSZS 4 1953029 2 1 __ 6,-6 - 8 cos (-S'O") + [0 sin (-50') = -— £4.80 Rs; 8 5M (-56) + to cos (-50“) = 0.30 ks; + 8 cos (-5'0" 3 - I0 am (-50“) = 20.80 ks." 26 = 20° - 8905 (20°) + 10 sin (10') 8 Sin (20.) “ IO (.05 (10°) + 8 60$ (20"3 " ID ca; (20') ‘- 3. 90 “5:- l2. l3 RSI. 12.10 ksf —‘ ...
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