{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

778_Mechanics Homework Mechanics of Materials Solution

778_Mechanics Homework Mechanics of Materials Solution -...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: _ _ (QC—J L—J (lo) PROBLEM 7 19 7.19 The centric force P is applied to a short post as shown. Knowingthat the stresses ' onplanea-aare a=-15ksiandr=5ksi, detennine(a)theangleflthatplanea-aforms with the horizontal, (b) the maximum compressive some in the pom. SOLUTION 3' PM 6’! -= 0 Tad ': 0 SJ : Gar-‘95:”. : -— E _ x P/JA ,_ (2. +0“ 3 , m A ,sghs“ —€A-a~# ‘P :: .5. ec/g {LIA-(flak ': é .AVEE Force (a) = aro'imaé Triangle :- [3.4 "‘ '5 l5 PROBLEM 220 Two members of uniform cross section 50 x 80 mm are glued together along 7.20 plane a-a, which forms an angle of 25° with thehorizmtal. Knowingthatdie allowable stresses for the gluedjoint are 0’= 800 kPa and r= 600 kPa, determine the largest axial load P that can be applied. SOLUTION q: 6‘ 325° "YI 1PM / For pique arcs 9:65" 1 |:I~X 65° 94! Y -33 Gar-A 6; C0516 4 SJ Sltnle +211} sin 9 as Q 3 O -i- B Sa‘nzcgo‘? o A .55.. - mWw—Xsoow) SinzéS" .. 51's." GS‘” = '(8; ~65} $896,059 + TU (50.519 - 5:339) = E sl‘nGSocOséf-l O p 3 A f : (Sm/o")(souo“)(eoouog 2 z 6.27,“): N sihwuséf" sin 65" cos (5" Ajflowae’oje Value 0‘? P is “Hue smquet‘. P: 3305403“ "" 3.?!) k” d r 330nm" N ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern