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781_Mechanics Homework Mechanics of Materials Solution

# 781_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 7.24 The steel pipe AB has a 102-mm outca- diameter and a 6-mm wall thickness. Knowing that am CD is rigidly attached to the pipe, determine the principal masses and the maximum shearing stress at point X. SOLUTION PROBLEM 7.24 13:39:- igz:51mm V2: ﬂ-t: ”SW" 2 J a EU} n“): 4.I355~lo‘wn"= 4425910" w." I” 'LJ- '-' 2-0927'70'“ In" Franc — Coupje syst'eln at" cem‘l'er 0—? +05: in “Hue Flinn: con‘lm‘m'nj PoM‘ts H mm! K F: = IOekN = Iowa" ~ My? (onlo3)(ﬂoo~to'3) e 2000 Hwy, M1: ‘(10*10'3(|Sonk3'3)v-l\$oo MM A} Poi-0+ K'J PJnce you} x-m‘s in logical-Jug 3.99154} z~ot\$reo+ion WK — Ia - W .. - ‘ .__ T3 I J ‘ 4.!855‘wro‘ " 2437““) Pa -- 24.37 MP4, T= My: 2000 M-M sz‘o TMnSVewse Shem»: S+ress clue he +mnsucws¢ shear V= E: is Zero whit K. Sudan: 16g: M149 = W "-' 36.56 uo‘ Pa -- 36.56 ”PA Raid K J’ies on caMPNSSleI sale 0-? neo+WJ «M‘s? 63=-3€.§_6 HP; Tow? s+nsses at Fooin'} k 6”,. = o 53 = -3a.5e. MPa J 2:, =2m37 MP6t 6‘... = ﬂé‘nﬁﬁr -l8.28 MPa 12 '(5135)‘+11; = 30.46 HPa 5 m -. Qua/R = —12.23+ 30.44. =+:2.t8 MPa 6....“ G... — 12 v — 13.22 - 30.44. = 413.7% MP4 73...... - R = 30.45 MPGL ...
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