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800_Mechanics Homework Mechanics of Materials Solution

800_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 7.46 7.46 Solve Prob. 7.24, using Mohr’s cirde. 7.24 The steel pipe AB has a 102-mm outer diameter and a 6-mm wall thickness. Knowing that arm CD is rigidly attached to the pipe, determine the principal stressw and the maximum; shearing 311633 at point K. 51 mm SOLUTION r0: 2'; =33; “yum nut-t =45”. = £09- (2“): LLJSSSxtcf mm” = 1:955:10" "I" I = 3% = 2.0e27xlo“ w Force—Coupfie sysiew. a'} cedar o-Fi-ube in He plane con'l‘m‘nenj Feller“, H awe] K F, = lowo3 N M3 = (10x103)(2oo~‘lo")=- 2000 Nam M2 = - ([0,109)(150y10'5 ) = - 1500 Hum J’l 'nrsfon: T: M3 = 2000 N-M c:n,=5:x:o"m 1K1 x 713’ %c' -' W = 24.37 MPa. F '+. IZSSX IO"c No‘l’c Hmi’ Inca} x-axu‘s is high ado-43 nejul'ivz 319.3de 2- ‘a/a'ner/Hon. Transverse Shear: SMSS clue {3 V‘ F; is Zem 0:” Fof-d’ K. Banokflfl: i631: M‘IC : MUSOOKSHIO") I 2.0927140" ‘— 36‘56 MP“ Poivd K flies on compresSfo-n Side 0" neo‘iw) Mfs. CE}: -3€.56 MPa. Ida} sire-$525 all Pain") K 6;= 0 , 63-" ‘35-56 ”Pa , ’11:, = 29.37 MP0. ’L’Mnm “’ 6.... = &(6'.+63\ r ~ I8.23 MP... 1 12: “gig”; + ’12; -: swig Mpg. . 6049..) 5...... = '61.... 4 F? = —l1?.'28 + 30.46 '~'-' I2-|3 MP1 «I ‘ 6'“... = 6..., - R e — raga — acme. - r -L|8.7'* Mpo. ‘ X ’1’...“ = 1? :- 30.?!- MPG. "- ...
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