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833_Mechanics Homework Mechanics of Materials Solution

# 833_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: *7.80Forthestateofsu-ess ofProb. 6 66, determim(a)thcvalueofq,forwhichthe PROBLEM 730 maximum shearing sums is as small as possible, (6) the corresponding value ofthe shearing stress. SOLUTION Let MES)”: GJ=6x—2u 70 A350»: 21., is He in-pﬁanc shearing dress 21..., Then tuna-6mm i‘s mm'WW-W u :0 03 6:: 20 = 6; = No MP4. J G‘M= Graeme MPA R = mt._,=- so MP“ 61:6; + R = - NO + so = 2.20 MP9. 6-5: Sau'R = HID-80 * 60 MP“- s’w = ' 220 mp4) 59;" = 0', rm = £62..“— mum no HPq Assumpﬂon {s ,n‘n camv‘t AtsuMe 6;“:6; = S“. +R "- 6', -u + u"+ ’21:," 61min 3 0 runs: 2<6m‘6‘H-M]= 476:. e562..- -1 + U 2f: 0 (no min-'mdm\ [Kuwa- uf-c-P 101m} "- 7mm ch: 101“} ;3(€.+R)‘ Pdvsa- Q or 5,—U=JU‘+11,‘ (6.;“U‘m 1" 61.174206; +f6‘. 3/6‘4'” ti; OP‘h'WHJM _ M419: .-Fof‘ Dz‘ OCCUM wkevx z ‘, 20 .— #11: #71:;- = 49,3 MP6. or 47.l"‘ MP“ ”‘1 # 6‘: 6,-20» |HO-‘i‘%.'\$= 45.7 MPa ‘ =-JU‘ + 21., Tm. = ‘?2.."i MPaJ "" ...
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