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866_Mechanics Homework Mechanics of Materials Solution

# 866_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 7.124 A brass ring oflGO-mm amide dimneter ﬁts exactly inside asteel ' of PROBLEM “24 160mm inside diameterwhen mempemme ofboth rings is 5° c. Knowmngtghat the tempemnn'eof the rings is then raised to 55° C, determine (a) the tensile stress 30 mm "seed-[meted ring, (6) the corresponding pressm'e exerted by the brass ring on the 3 mg. SOLUTION E, - 210 GP». . a, - 12 x 104%: BRASS Le'l' P be Hm ‘-°"+w+ Pressure bdween 33%;, ‘Hae rings. Subscn’pi‘ s re-Fers Jrt: "Hae si‘ee) a:-20X10'6I°C V‘inﬂ. Sabamn‘p‘i‘ b re-Fers +0 H12 brads Nina. r Siee! V‘I'Mj'. Ionian-.5} Pregsgﬂ P.) 6:5 %; (n . 6;. V‘ CorrGSPomalinj 5+V‘aun 85?: E = 2"“ Strain clue +0 +Ev~1pert~+um clnawije 551- '-' 015 AT To'i’aj s+v~m'm 5; = 2!:- -\- 0!; AT- Eats Cleanse. in Jena‘Ha oi CL'M‘ouM‘Fewemcg __.. 3L5 = 21mg ._. .1217y~(-Elr‘fs +o£5 Al) F Bra—\$5 Neat Evie-Mm} PNSSUH‘ P.) 6‘}, = — %: Correeponoli'nﬂ SMMS Eb? 1' - 5;. J EbT = 0.", AT Change in yang-Hi o'F Ci'MuM'Pewenc-e Y‘ ALE : 27TH}, = 217w (~ ﬁg. + 01.,AT) Equui'hnj AL; “in All, En+ (is-AT : _ \$5 + db AT ) p = (db-om AT (21 55°C ~\$° =- .5’0"d é’d : 90 Mm 80:40" 90:10" E g _ -c. rm“ e" (2‘ 5 [ZIOVIO‘)(‘1MO")+ (loswo‘)(‘mo“) P (8"0 )Csoi 285.7lx16“ P 2 40mm“; p= Lawn)“ R; M = 21‘ , (1.wo‘)(3ouco“) = s Fru 8.1.0) 6:5 is WHO" 28 x10 Pa (DA 65 = 28.0 MPGL “ i on p = 1.400 We; ...
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