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867_Mechanics Homework Mechanics of Materials Solution

# 867_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 7.125 STEEL t, - 4 mm E3 - 210 CPa a,- 12 x were ' BRASS t5 - 4 mm Eb - 105 GPa ab a 20 x 104%: 7.124 A brass ringoflﬁo-mm outside diameter ﬁts exactly inside asteel ringof 160-mm inside dimeterwhmthe temperature ofboth ring is 5° C. meingthm the temperature ofthe rings is then raised to 55° C, determine (a) the tensile sums in 11?: _steel ring, (b) the corresponding pmsme exerted by the brass ring on the stee nag. 7.125 Solve Prob. 7.124, assumingthat the thicknms ofthe bass ring is t, = 6 mm. SOLUTION 1.9+ P be Hm, eon'l'aci' Pressure be‘hueen 'Hne w'nas. Subseru'P+ S re-Fers +6 'Hae. s‘f‘eeJ’ Wing. SoBscvu'p‘i' b V‘s-Few; +0 ‘Hae brass r‘ﬁnj_ Shae} Y‘I'nj'. In‘lernaﬂ Pnggsgﬂ P.) (3; : 55 (n 6, Ex: Correspomdr‘nj S‘hﬁeu'n 85?: Es- : ﬁts s+min clue +e +emperu-fuw; clnawuje Ear: 01; A?” To'i‘aJ s‘l’was‘n £5 = PJ‘— -\~ 0!, A1- Eats Change. in Jenj‘Ha <3" Cl'V‘oum‘FQ-fence __ AL; = 21mgs = “ME; ”‘6 4" Bra-SS Ping: EH-ewnal PMSSUM P.) V‘ 6h=_%. Cow-responalz'nrl 5MIns Eb? - 5% J E“- = db AT D Clnanﬂc in Icing-H: 0'? cl'mumpev-ence __ _ _ Y‘ ALL — 27rv~65 — 211m ( ﬁt + 04,111“) E79~+;hj AL: +0 I... .11. (Eats + at.) F ALL Erh+d5AT:—ﬁb+dbdr = (a5‘ as) AT (23 Dede: jAT = 55°C - 5°C = 50°C 7:5: Guam = 65:10.3m r: 4'6": (zond’) (game's) , FM“ 91' (2) {utowo‘lmkto‘i )+ W; P 212 - -3 9. = \$12 = (Lanto‘ Meow: ) = 36,109 Pa 3 Fv‘om a?!” 20 MM " (8%!0“)(5o3 22 vlo'w‘ P = Lloo wto‘j p: Lib-to" Pa. H )‘tlD’3 ...
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