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885_Mechanics Homework Mechanics of Materials Solution

# 885_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 7.149 Thcﬁillowingmteofstminhasbeen detenninedmthesm‘faeeofacast— PROBLEM 7.149 iron madtine element: 6. =-720 X 10“ inJ'm. ' a, a 400 x 10“ MIL r=+660 x 10“ rad .meingthatE== 10 x lO‘psi andG =4 x 10‘ psi, detemﬁnethe principal planes and the principal stresses (0) by determining the con-impending state of plane stress [use Eq. 2.36, page qq‘Eq. 2.43; page at ; and the ﬁrst two equations of Prob. 2.75, page W} and then usmg Mohr’s circle for mess, (b) by using Moir’s citcie‘ for strain to determine the'orimtation and magnitude ofthe principal strains and than dammmmﬂmmmammmmmwma SOLUTION - E' _ _E__ _ I0 _ = G - 20”,, v- 26 — I - mm 0-2.5 Note it“; :ECMSV‘A 6 Pr‘unaopq 54 £75." t wit: : JO.GC7¥IO‘ Fat. 6c=o 4‘ (0.x 6‘. - E (saved = mesh/0‘ [-7zoxto" + (o.zs)(-qoouo“‘ﬂ "w - —2746.7 Psi = l0.6é7wlo“ [-4ooxzo“ + (0.2530720 wwﬂ : -6'86d7 rial. 1: = GY = (4xlo‘)(ceowo") = 2640 Psi mam gm = ﬂaw}; = ~7466.7 ’91-" 2’1: +61” 295: €— 6; 2‘2. 0625 eh: - 32.n" 6v 519° l =( \‘l+,r—tl: 293‘] psi 67,.: 62“ + f? = - «533 psi 4 6;: 6—...” — R = _ quoo. PSI "‘ G (5) em = £(E.+s,_)= —.S'60v{o' Y‘ _ €50 _ _ are; ' w7zoe‘ioo 2-0625 29.5-54.1" 95.....32” 9.; 519° )1 +01 29,, = 341234 x lo“ i Sgt-3535146“ Web) = ‘14533 ref ...
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