906_Mechanics Homework Mechanics of Materials Solution

# 906_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 7.03 (a) Write a computer program that. for a given state of plane stress and a given yield strength of a ductile material, can be used to determine whether the material will yield. The program should use both the maximum- shearing-strength criterion and the maximum-distortion-energy criterion. It should also print the values of the principal stresses and, if the material does not yield, calculate the factor of safety. (b) Use this program to solve Probs. 7.81 through 7.84. PROBLEM 7.C3 SOLUTION U42: WIMJJM —- {Hem we - 5mg; C 2: aria/M fr“ r’“ ._ _ I /F Vi my )8 ﬁrst»? semen Sid/V) 70;“); 5'7; /F 7;,” 7 7;) ”#01ng 00¢:sz //—" 7;,” < ‘7‘?) N0 ”gig/xv; occ: Lei-4‘5, ”MID i 7;.» Mawa— ﬂf7b/k7‘VaN— 5—2155; r (,2.- } TfﬁmN M Fan‘for’? or: \$454.57? 1" 2 COMPLY»? 33mg.“ =Vq; _. go“; 4.. 3-52 F 1298!)!an > G" Y, 49W: army/a; Y.) i _ I]: [2,;M/frﬁl (M W) N0 Y/[AO/jvé C356. LIV-31\$, I73? m. V? RHUKHL WW F2570»? 0/: 54/6577: Pa; 12;; M 00 TPU 7 Problems 7.81a and 7.82a Sigma x = 36.00 ksi 21ksi Sigma y =- 21.00 ksi ‘ Tau xy :1 9.00 ksi ——~—-—- RFC? ksé Sigmax a 40.22 ksi " Sig-ruin = 16.78 ksi Using the maximum—shearing—strese criterion: ‘ =‘ 36ksi Material will not: yield F.S. = 1.119 Uaing the maximum—distortion-energy criterion: Material will not yield F.S. = 1.286 CONTINUED ...
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