940_Mechanics Homework Mechanics of Materials Solution

940_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 8.25 The solid shaft .43 rotates at 600 rpm and transmits 80 kW from the motor M PROBLEM 3-25 to a machine tool cemented to gear F. Knowing that I.“ = 60 MPa, determine the smallest permissible diameter of shaft AB. SOLUTION 'FT-m =IOH2 ".13.. -_8_Q__t_o_‘_- _ T '21:? (211300) _ m”- N '" Gear C E=~E :- 153?:3 no“ N _ 1273.2 F; ' 80x10“ 1' GER? D Pa = F;- [273.2 :- -.-_.—————- = o E” GONG" 21.22:” N Forces In Ver‘ll‘ea) inflame. Mm = (:20 H04 l(%, E) = 1335.7 N-m Mm: EQEEMH : 572.9 N-m Forces. in havizon‘la.’ Pfiqne Moj=(lao>«to")(fi;Fo)= 1722.; N-m A‘l'C: Mfd- M:+T" = ”7°71? N-m M D: 4‘ Matt" Mt‘iTL = 22:24.3 N-m ’1’.“ = %( MJ1+ M:+T" )M‘m All 2 '¥C.3“ (1M;‘+M1 +T _ 26 ’5 = 37.73'8x10“ m3 Gowo‘ c = 23.2953... ot=2c - 57.7xto“m : 57.7 m. --u ...
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