1007_Mechanics Homework Mechanics of Materials Solution

1007_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 8.C5 - CONTINUED fllyar- (mar/u: .5. 01(7374 -——--———-——.&.._——-_ We *9: v3= *3sz vim.- M3 = Why/5%.; = ~ :c» A?» m. M; -(3«&yJX/0' . — 4* 41,): ~ 33 43 we. 1%”??? 5:257. {Au—~71}; E£9§i§E_§;§9 Force-Couple at Centroid P -24.ooo kips MY -30.000 kip-in. MZ —33.000 kip-in. VY 3.000 kips VZ 2.000 Rips +++++++++++++++ +++++++++++ At point of coordinates: y a 2.000 in. 2 -2.000 in. sigma a 1.792 ksi tau = 0.104 kai ———————————— ..._-._.___...——-,__————_—.,..-____.._____._.._.1..,___.. PPOEZFM c9. 5.? POM/7‘ r? 60mm ,2 Evan: ”(0052:; 5 575M 2 -/20»fi/>’ Vijrfofizv M3: (zanOJsz Z—QN-m M2.— (MM/Wows on) +(w&~¥o./w) =r flag/Via» paw? 2’7! fl= ?0 9W4?! E'= 30mm» Problem 8.53 Force-Couple at Centroid P —120000.00 N MY 2000.00 N-m M2 = 11000.00 N-m W 50000.00 N VZ = ~20000.00 N +++++++++++++++++++++++++++ At point of coordinates: y = 20.00 mm 2 = 30.00 mm sigma = —14.352 MPa tau = 9.259 MP3. ...
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