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1056_Mechanics Homework Mechanics of Materials Solution

# 1056_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 9.46 For the: beam and loading shown, determine (a) the slope at end A, b the PROBLEM 9‘46 deﬂection at point C. Use E = 200 GPa. ( ) SOLUTION I Unik: Farces 3:11 It”; [Pens-Has In WI ‘. W150x13.5 +3 M1: = o — [.6 RA +(?.G.)(O.8)+(2a)(o_‘i) = 0 RA 1' 9.8 k" wa3 = 39. (x-o.u)° - L24)“ L27° kw... —w(x) = — 12.<x-o.cc)°+ _|2-<x-:.2)° WI.“ 9.2 ._ 12 <x—o.‘+)' + :2 (x-:.27' - 20(2— :.2>° w my - G<x—O.9)z+ 6(x- :.2)‘— 20¢- :.2>' kN-m « 457,8 — 20-0.4? + 2<x— :.2>’——Io<x—I.z)" + C. I. kN- m E13 = Lesass x!“ - ﬁ-(x—oA)” 4 5'4):— L2>"— 1320- L2>s + qx 4 cl . 1 [wodw] o-o+o-04o+c2_=o C2 '= O [mtmwl (Lesasmacf- £0.03 -;(o.4)"- 13-?(034 )3 c.(:.c)+ o c, = - 3.4030 kN-m" Daﬁla: E: Zooxto‘ Pa. 1‘:- 6.87110‘ um" =0 enable“ m." EI =(200xlo‘)(c..87xto") r L37qwo‘ N-mz " l379 Ind-m" (O—\S.Pof:ea1lA (at: dx=03 El'f'g‘: 0—0 +0 —0 53.4080 kid-m“ 9A -.-_ W 2 -2_48¥lo"3m4! '= zqgud’mA-‘a‘ (b) DC‘Flec‘Ho-A a.+ C ( J 6v+ X“: 1.2M) {513; = (3.633333n.2)3— gas)“ + o « o -(3.qoso)CI-2) +0 = - Luna. L’U-m’ J4 '. - I 5:. = ' [137220 t 'I.O7IHO‘M ‘-' LO“ "M“‘l’ ...
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