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1065_Mechanics Homework Mechanics of Materials Solution

# 1065_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: deﬂection at C. Use E a 29 X 10‘ psi. SOLUTION who = L5 ac — ‘Kx-GS - l.\$<x-s)' JV x AM- Eli'i = inf— o.oczsx"+15<>¢-e>' + 0-06250-‘9 + C. EIX ’ ELEMS- 0.0125 x“? + 0.3756"; + 0.0’256‘4)‘ * C. x + C'— [i=0.3=0] o+0+o+o+O+C‘=o Cz [xugj—gw] imam? —(0.062§)(12Y'+ (I.5)(¢.]’+Lo.0625')(6\" + C. = C. = '21: - 12 R. = o law-H‘ [xa 12) 3 :0] £9.02? 40.0125 Km“ a-(o.37§')(e\" 4 (0.012s)(e>‘ +(8ﬁl-729n)(12)+o = o (8:4 - 223m : 8|(4-8 R. = H. r15 laps 1‘ C1,: 34: 472102.175) = «me 149-439 Duh-3 E = 2%:0‘ Psi = zaluo’ ks: = 15¢ w E1 = (ZQKIO’XIS’Q = H.521x10‘ku'r-inl = 3Hl7 tap H“ (b) Dcrjeo";ola 09+ (1 C] 0+ X“ G) El 5; = é (H.175)(e)3 - (o.o:as)(c)5+ o + 0 -(f2‘7.é)(‘-) 4 O = - sets brat?" _ _ 361.5 1'- ' 3H1? = -- ILCDHO" 'H' (D.l3‘12 'm J, PROBLEM 9.55 9.55 and 9. 56 For the beam and loading shown, determine (a) the reaction at A, (b) the T : -w(x) = —l.5x + ‘I<x-67D+ l.5<x-6)‘ 742 - V -. 9A -o.75'x‘ + ﬁ<x~67| +0.7s(x-6)‘ Elﬁi = M '-' 2.x - 0.25)? + 4.5(31-6)‘ + 0.256969 Mf-‘H’z kIP-‘H. = O D ...
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