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1130_Mechanics Homework Mechanics of Materials Solution

# 1130_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 9._120 For the beam and loading shown and knowingthat w = 8 mm, determine (a) the slope at end A, (b) the deﬂection at the midpoint C of the beam. Use E = 200 GPa. PROBLEM 9.120 40 L'N - In SOLUTION D x E = 3003‘“)It ‘Pa, wamxso - I = I24wlo‘ mm." = IZQon‘m" EI = (200 uo‘mzeuo“): 25.910“ um: = 25800 kNa In" Sjmme+rfcm€ beam and IDA-aﬁnj. Q = P3 = H2300) = 1+0 w Bending manner? M = .40x - 40 ~ 2'19“} M x = S M: 200 - 40-100 L Draw '5? Jay-am L3 Fund's. 13:1: Nah-5.4 5?: = {is-E: r. 7. 751nm: w: E:- r 252w = - 1.5504ho m "E? = 2530 —.. — answers" m" A, .- ﬂvnsmuodﬂs) = masoxlo" >7,=(%[5\= 3.3333 m A1 .- -0.5504)(5) = -7.7520r!0-3 saga-pm = 2.5‘ m A“ e~3'3-('.-'>.\$3'Iéo)(5) ? - 6.46m» 19'5 is = (*EMS) r 3.75 m PP“; rc'FeJ-ence +am38n+ a,+ C 9c. : D (a) SPOPQ 6.2+ A. 9, 2 96- Sc,“ 3 O "" (Ar! A; -} A3) s g, = —(I°L\$30ylo'3— Zuzana)“ — c.4609xro‘3') e 2-5.l7xio_ m4 4 03‘ De'rletr'i’a‘ou a.+ C ljc‘? tAfc. = (lq.380¥lo'3)(3.33537-(7.75205'10'3K253 - (c.4coovso” Mans) — Zlonodm ~= 2|.o Mal. .- ...
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