{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

1219_Mechanics Homework Mechanics of Materials Solution

# 1219_Mechanics Homework Mechanics of Materials Solution -...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 10.28 Column AB carries a centric load P of magnitude 7: kN. Cables BC and BD PROBLEM 10,23 are taut and prevent motion of point B in thexz plane. Using Euler’s formula and a factor of safety of 2.3, and neglecting the tension in the cables, determine the maximum allowable length L. Use E = 200 GPa. SOLUTION 4 W 250x 32.7 I = usﬁwo‘m. :- 1.3;, .7 )l W250X32 1:] ‘- H.73¥10‘Mmq= 4.73 >< 16‘ m" P: 72 no’ N Rowln=(Es.)CP>—-rastawo’ N Baokﬂnﬂ in X'Z—frpane: Lg 0.7L .. WEI, ' (6.713) .17... E; 0-7 Pu Wv— ~-- u IL (290pr X 4.73 x (5'93, OJ IES‘LEWC‘)’ 3 30.74 m 17ng:- BUokjinS {n ‘yZ—p’l’anc: L: 3' 21- Pcrt W _ F EL: Tl' ooxto‘t 48. to" _ L"'2"V“PL = “2‘ 165:3XL0; “ ”'08 m 10.29 An axial load P is applied to the l.25-in.-square aluminum bar ABC as PROBLEM ”'29 shown. When P = 3.3 kips, the horizontal deﬂection at and C is 0.16 in. Using E = 10.1 x 10‘ psi, determine (a) the eccentricity e of the load, (b) the maximum stress in the tod. SOLUTION 4 , ‘ I = \$045) -' 0.203145%)" A -:.1_25‘= L325 m“ L; = 2L : 50 In L: 3 2L =501'n. .. 2 x o Ill—Eb}. = 7’ (l?-Sl_dlg>1)(O-2°3‘*\$) : immune? ﬁlo. e . 3 8 x103 SJIZAXIOS - e): sec(§f-§m)- I] = €[Sea('gm)" = e[5u(l.o7:>‘os)- i] = [1.1023 e 2 1.... _ one. 2 3 Lucas ’ 1.1023 0"”5‘ ”‘ “’5 Mm:- P(e+ 1...):- (3,3x:o=)(o.ms:+ 0.16) = Lisa\$7 lb-in 3. :3 (l.ls=157)(o,52§)_ 1 ,,__ .‘ €m= {H -}-"-9- 1.5350 + “as“ - 5mm: f». 5.1? ks «a -‘ O.’468'—l2 Li AI-—A ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online